🧠 Amazon Interview Experience — Binary Trees, Backtracking, and Greedy Algorithms
Overview
This case study examines a candidate's experience during an interview process at Amazon. The technical assessment focused on a range of algorithmic topics, including binary trees, backtracking, and greedy algorithms. The interview comprised several rounds, each designed to evaluate the candidate's proficiency in problem-solving and coding.
Interview Rounds
Round 1: Initial Assessment
This round involved algorithmic questions related to data structures, specifically binary trees.
Problem 1: Maximum Average Subtree
The candidate was asked to find the maximum average subtree in a given binary tree.
Approach:
A post-order traversal approach was used. For each node, the algorithm calculates:
- The sum of the subtree
- The number of nodes in the subtree
- The average, which is then used to update the global maximum average.
class TreeNode {
constructor(val, left = null, right = null) {
this.val = val;
this.left = left;
this.right = right;
}
}
function maximumAverageSubtree(root) {
let maxAvg = -Infinity;
function dfs(node) {
if (!node) return { sum: 0, count: 0 };
const left = dfs(node.left);
const right = dfs(node.right);
const sum = node.val + left.sum + right.sum;
const count = 1 + left.count + right.count;
const avg = sum / count;
maxAvg = Math.max(maxAvg, avg);
return { sum, count };
}
dfs(root);
return maxAvg;
}
Problem 2: Backtracking on Array (Subset Sum)
The candidate faced a classic backtracking problem, specifically the Subset Sum problem.
function subsetSum(arr, target) {
const result = [];
function backtrack(start, path, sum) {
if (sum === target) {
result.push([...path]);
return;
}
if (sum > target) return;
for (let i = start; i < arr.length; i++) {
path.push(arr[i]);
backtrack(i + 1, path, sum + arr[i]);
path.pop();
}
}
backtrack(0, [], 0);
return result;
}
Round 2: Face-to-Face (Amazon Chime)
This round was conducted via Amazon Chime.
Problem 1: Zigzag Tree Traversal
The task was to implement a zigzag (level-order) traversal of a binary tree.
function zigzagTraversal(root) {
if (!root) return []; // If the tree is empty, return an empty array
const result = []; // This will store the final zigzag traversal
const queue = [root]; // Use a queue for level-order traversal
let leftToRight = true; // Toggle direction at each level
while (queue.length) {
const size = queue.length; // Number of nodes at the current level
const level = []; // Temporarily store values for this level
// Traverse all nodes at the current level
for (let i = 0; i < size; i++) {
const node = queue.shift(); // Get the front node from the queue
// Add the node's value in the appropriate order
if (leftToRight) {
level.push(node.val); // Insert at the end for left-to-right
} else {
level.unshift(node.val); // Insert at the beginning for right-to-left
}
// Add children of the current node to the queue (for next level)
if (node.left) queue.push(node.left);
if (node.right) queue.push(node.right);
}
// Add this level's values to the result
result.push(...level);
// Flip the traversal direction for the next level
leftToRight = !leftToRight;
}
return result;
}
Original Source
This experience was originally published on medium. Support the author by visiting the original post.
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